The temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr is 276 K or 3°C.
Charles's law states that, "When the pressure on a sample of a dry gas is held constant, the Kelvin temperature and the volume will be in direct proportion".
According to the given information:
V ∝ T
V/T = K
Where,
V is the volume of the gas,
T is the temperature of the gas (measured in kelvins), and
K is a non-zero constant.
In two different states, an initial state 1 and a final state 2, the equation is,
[tex]\frac{V 1}{T 1}=\frac{V 2}{T 2}[/tex]
Given data:
V1 = 11.2L
V2 = 13.3L
T2 = 55°C = 328K
By substituting the given data,
[tex]\begin{aligned}&\frac{11.2}{T 1}=\frac{13.3 L}{328 K} \\&T 1=\frac{11.2 L / 328 K}{13.3 L}\end{aligned}[/tex]
∴T1 = 276K = 3°C
The temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr is 276 K or 3°C.
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