The height, h, in feet of a ball suspended from a spring as a function of time, t, in seconds can be modeled by the equation h = a sine (b (t minus h)) k. what is the height of the ball at its equilibrium?

Respuesta :

Based on the height of the ball suspended from a spring, the height of the ball at equilibrium is K feet.

What is the ball's height at equilibrium?

The model for the height of the ball when it is suspended from a spring is shown as:

= aSin(b ( t - h)) + k

Given this, we can infer the value of h by looking at the general form of the Sin function which is:

y = Asin(Bx) + c

In the above:

A = amplitude

B = (2 x pi) / Period

C = midline

Comparing the function and the general Sin function, we notice that:

C = K

If C = K then it means that K is the height of the ball at its equilibrium because C as the midline represents the equilibrium height.

In conclusion, the height of the ball at equilibrium is K feet.

Find out more on a ball's equilibrium height at https://brainly.com/question/15627638

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