The resistance, r, to electricity of a cylindrical-shaped wire is given by the equation r = startfraction p l over pi d squared endfraction, where p represents the resistivity of the wire’s material, l represents the length of the wire, and d represents the diameter of the wire. what happens to the resistance of the wire as the diameter approaches 0?

Respuesta :

As the diameter of the wire approaches to zero, the resisitance approaches  infinity.

What is resistance?

Electrical resistance is the physical capacity of any body to oppose the flow of electric current even when there is an applied potential difference, capacity calculated by Ohm's First Law, and, according to the International System of Units (IS), is measured in ohms.

With that being said, and knonwing that:

R = Resistance; p = Resistivity; L = Length; d = Diameter

It is possible to calculate the resistance of the wire by:

[tex]R = p\frac{L}{A}[/tex]

Where A is calculated by:

[tex]A = \frac{\pi d^{2} }{4}[/tex]

Changing in the first formula:

[tex]R = p\frac{L}{\pi d^{2} } \\\\R = p\frac{4L}{\pi d^{2} }[/tex]

Knowing that when the diameter tends to zero resistance tends to infinity, it is possible to say that resistance of the wire will tend to infinity when the diameter approaches zero.

See more about eletromagnetism at: https://brainly.com/question/13407121

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