The end behavior of the given function (range) is x< 4 or x > 4. So, f(x) < 4 or f(x) > 4. The solution in interval notation is [tex]\mathbf{(-\infty, 4) \cup (4, \infty)}[/tex].
The last option is correct.
What is the range of the function?
The end behavior of the given function f(x) = (8x+1)/2x-9 wants us to identify the range of the given function.
The range is the set of values of the dependent variable for which a function is defined. The function range is the combined domain of the inverse function.
From the information given:
[tex]\mathbf{f(x) = \dfrac{8x +1}{2x -9 }}[/tex]
Inverse of [tex]\mathbf{\dfrac{8x +1}{2x -9 }}[/tex] becomes [tex]\mathbf{f(x) = \dfrac{1+9x}{2(-4+x) }}[/tex]
The domain of the inverse is x< 4 or x > 4. So, f(x) < 4 or f(x) > 4. Now, representing the solution in interval notation, we have:
[tex]\mathbf{(-\infty, 4) \cup (4, \infty)}[/tex]
Learn more about the range of a given function here:
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