Respuesta :
274 amu
Explanation:
Atomic weight of Na = 23
Atomic weight of Sio3 = 76
then,
molecular weight of Na2Sio3 = add 23*2 and 76*3
= 46 and 228
= 274 amu
Answer:
Answer:122 g/ mol
Answer:122 g/ molExplanation:
Answer:122 g/ molExplanation:first must find the molar mass of each element in the compound
Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/mol
Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/mol
Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ mol
Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ molhence , summation of the molar masses
Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ molhence , summation of the molar masses46+28+48 = 122g/mol