The total surface area of the tower composed of a prism with a square base and a pyramid is 3600 + 400√2 m²
Total surface area of the tower = area of the base + 4(area of the rectangular surface) + 4(area of the triangular surface)
Therefore,
area of the base = 20² = 400 m²
4(area of the rectangular surface) = 4(40 × 20) = 3200 m²
4(area of the triangular surface) = 4(1 / 2 × 10√2 × 20) = 4(100√2) = 400√2 m²
Therefore,
total surface area = 400 + 3200 + 400√2
total surface area = 3600 + 400√2 m²
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