Consider the following data set.
45 58 41 45 38 46 45 39 40 31
1.
Sort the data and find quartiles of the data set.
2.
Find the interquartile range of the data set.
3.
Find the lower fence and the upper fence for outliers.
4.
Find outliers if they exist.

Respuesta :

Based on the dataset given, the first quartile is 38.75, and the third quartile is 45.25. This interquartile range is 6.5. The lower fence is 29 and the upper fence is 55.

What are the quartiles in the data?

Order the sets:

31, 38, 39, 40, 41, 45, 45, 45,46, 58

First quartile position:

= 1(10 + 1) / 4

= 2.75th position

= 38 + 0.75 x (39 - 38)

= 38.75

Third quartile:

= 3(10 + 1) / 4

= 8.25th position

= 45 + 0.25 x (46-45)

= 45.25

Interquartile range:

= 45.25 - 38.75

= 6.5

Upper fence:

= 45.25 + (1.5 x 6.5)

= 55

Lower fence:

= 38.75 - (1.5 x 6.5)

= 29

59 is an outlier.

Find out on the interquartile range at https://brainly.com/question/4102829.

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