A 80-kg base runner begins his slide into second base when he is moving at a speed of 3.0 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base.

(a) How much mechanical energy is lost due to friction acting on the runner?
______J

(b) How far does he slide?
________m

Respuesta :

The mechanical energy lost due to friction is 360 J.

The distance the runner slides is, s = 0.655 m

What is the mechanical energy of the runner?

The mechanical energy lost due to friction acting on the runner is equal to the change in kinetic energy.

Change in Kinetic energy = 1/2m(v -u)²

Change in Kinetic energy = 80 * (0 - 3.0)²/2

Change in Kinetic energy = 360 J

Mechanical energy lost = 360 J

Distance he slide is determined using the formula below as follows:

Acceleration of runner = coefficient of friction * acceleration due to gravity

acceleration, a = 0.7 * 9.8 = 6.86

v² = u² - 2as

s = v² + u²/2a

s = 0 + 3³/2 * 6.86

s = 0.655 m

In conclusion, the mechanical energy lost due to friction is the loss in kinetic energy.

Learn more about friction and kinetic energy at: https://brainly.com/question/20241845

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