We know for a fact that the equation:
[tex]|z+z'| \leqslant |z|+|z'|[/tex]
holds for any 2 complex numbers

I came up with the conclusion that:
[tex]|z+z'|=|z|+|z'|[/tex]only holds when z and z' are pure imaginary or pure real numbers of the SAME sign.
How can i prove this algebraically/geometrically?
Note: Irrelevant answers will be reported

Respuesta :

They don't need to be pure real or imaginary. Any "mixed" complex number works so long as [tex]z=z'[/tex].

Let [tex]z=z'=a+bi[/tex]. Then

[tex]|z+z'| = |2a+2bi| = 2 \sqrt{a^2+b^2}[/tex]

[tex]|z| + |z'| = 2|a+bi| = 2 \sqrt{a^2+b^2}[/tex]

so [tex]|z+z'|=|z|+|z'|[/tex].

The geometric interpretation is essentially identical. [tex]|z+z'|=2|z|[/tex] is a complex number twice the distance away from the origin in the complex plane as [tex]z[/tex], which is exactly [tex]|z|+|z|[/tex].

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