See below for the solution of each question
The points are given as:
(3,60) and (5, 80)
The equation is calculated as:
[tex]C(n) = \frac{C_2 -C_1}{n_2 -n_1} * (n - n_1) + C_1[/tex]
This gives
[tex]C(n) = \frac{80- 60}{5-3} * (n - 3) + 60[/tex]
Evaluate the quotient
C(n) = 10 * (n - 3) + 60
Expand
C(n) = 10n - 30 + 60
Evaluate
C(n) = 10n + 30
Hence, the relation of total cost, C, and number of hours, n is C(n) = 10n + 30
The point (3, 60) means he paid $60 for 3 hours
Here, we have:
Fixed = $10
Hourly rate = $15
The equation is calculated as:
C(n) = Fixed + Rate * Number of hours
This gives
C(n) = 10 + 15n
Hence, the relation of total cost, C, and number of hours, n is C(n) = 10 + 15n
The equation is represented as:
C(n) = 10 + 15n
See attachment for the graph
This is the point where the two lines intersect.
From the graph, we have the point of intersection to be:
(n, C(n)) = (4, 70)
This means that the charges for Comput-Repair and Data-Fix are the same after 4 hours
Based on the point of intersection, it is best that Jargit uses Compu-Repair because they have a lesser hourly rate
Read more about linear functions at:
https://brainly.com/question/4025726
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