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A thin flexible gold chain of uniform linear density has a mass of 17.1 g. It hangs between two 30.0 cm long vertical sticks (vertical axes) which are a distance of 30.0 cm apart horizontally (x-axis), as shown in the figure below which is drawn to scale.
Evaluate the magnitude of the force on the left hand pole.

A thin flexible gold chain of uniform linear density has a mass of 171 g It hangs between two 300 cm long vertical sticks vertical axes which are a distance of class=

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okpalawalter8

The magnitude of the force on the left-hand pole is mathematically given as

f'=0.167N

Q=45 degrees

What is the magnitude of the force on the left-hand pole.?

Generally, the equation for Force is  mathematically given as

F=mg/sinФ

Therefore

F(17.1*10^{-3})*9.8/sin 45

F=0.237N

Considering horizontal axis or plane

f'-fcos=0

Therefore

f'=0.237*cos45

f'=0.167N

In conclusion, the slope

tanФ=30/30

tanФ=1

Ф=45

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