This is a uniformly accelerated rectilinear motion exercise.
To start solving this exercise, we obtain the following data:
To find the acceleration, divide the change in velocity by the time over which the velocity changed. The SI unit of speed is the meter per second (m/s). To find the acceleration, the velocity is divided by the time expressed in seconds (s). Therefore, the unit of acceleration is m/s².
We apply the following formula:
[tex]\large\displaystyle\text{$\begin{gathered}\sf a=\frac{V_{f}-V_{o}}{t} \end{gathered}$}[/tex]
where,
We substitute our data in the formula and solve:
[tex]\large\displaystyle\text{$\begin{gathered}\sf a=\frac{20 \ m/s-45 \ m/s}{0.5 \ s} \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf a=\frac{-25 \ m/s}{0.5 \ s} \end{gathered}$}[/tex]
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf a=-50 \ m/s^{2} \end{gathered}$}}[/tex]
Answer: The acceleration when the ball slows down is -50 m/s².
The uniformly accelerated rectilinear motion, also known as uniformly varied rectilinear motion, is one in which a mobile moves on a straight path being subjected to a constant acceleration.
Final Speed (Vf) = 20 m/s
Initial Speed (Vo) = 45 m/s
Time (t) = 0.5 sec
Acceleration (a) = ¿?
To calculate the acceleration, subtract the initial velocity minus the initial velocity, divided by the time.
To solve, we substitute our data into the given formula:
Answer: The acceleration with which the ball stops is -50 m/s².
