$1,000 is deposited into a savings account. interest is compounded annually. after 1 year, the value of the account is $1,020. after 2 years, the value of the account is $1,040.40. this scenario can be represented by an exponential function of the form f(x)=1000(b)^x , where f(x) is the amount in the savings account, and x is time in years. what is the value of b ?

Respuesta :

The value of b is [tex]1 \cdot02[/tex].

What is compound interest?

Compound interest is when you earn interest on both the money you have saved and the interest you earn.

Formula for compound interest is

[tex]A= P(1+\frac{r}{100})^n[/tex] ...................(1)

where, A = total amount( principal + interest )

r = rate of interest in compound interest

n = number of years

Given,

For [tex]n=1[/tex]

Principal amount [tex]p=\$ 1000[/tex]

Total amount [tex]A=\$ 1020[/tex]

For [tex]n=2[/tex]

Principal amount [tex]p=\$ 1000[/tex]

Total amount [tex]A=\$ 1040[/tex]

This scenario can be represented by an exponential function of the form of [tex]f(x)=1000(b)^x[/tex]

Comparing the above function with equation (1), we get

[tex]A=f(x)\\P=1000\\b=(1+\frac{r}{100})[/tex]

For 1st year

[tex]f(x)=1000(b)^1\\\Rightarrow 1020=1000(b)\\\Rightarrow b=\frac{1020}{1000}\\\Rightarrow b= \frac{102}{100}\\\Rightarrow b= 1\cdot02[/tex]

now, check the amount for 2nd year

[tex]f(x)=1000 \times (1 \cdot01}^2\\\Rightarrow f(x)=1000 \times \frac{102}{100}\times \frac{102}{100}\\\Rightarrow f(x)=1040[/tex]

Hence, the value of b is [tex]1 \cdot02[/tex] .

To learn more about compound interest from the given link

https://brainly.com/question/24924853

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