22/7 was considered while choosing the square's side length, the area of just one side of the remaining paper which is a multiple of 7.
Since the largest circle that can be encircled by a square has a diameter "d" equal to its side length, we may use "d" to conveniently calculate both the square's area and the circle's area.
The largest possibly circle has been cut from a piece of paper.
Square’s area = [tex]d^2[/tex]
Circle’s area =ᴨ[tex]d^2/4[/tex]
Simplifying-
(divide both area by [tex]d^2[/tex]) we find their ratio is 1:(ᴨ/4) or 4/ᴨ (square: circle), and the inverse, ᴨ/4 circle: square.
Therefore diameter of circle =14 cm.
Hence area of circle=πr2.
If you use 22/7 as an approximation for ᴨ, the circle’s area 22/28 of the square’s, the square’s area is 28/22 of the circle’s , it follows that the area outside the circle is (28–22)/28 of the square’s area, which is (28–22)/28 x 14 x14,
or 6/28 x 14 x 14,
or 3/14 x 14 x 14,
or 42 square inches or-
(4-ᴨ)/4 x 14 x 14
22/7, It's a rather accurate estimate.
22/7 was considered while choosing the square's side length, which is a multiple of 7.
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