If AH=13mm, A F=15mm, and FC=37mm, what would be the distance between A and D? Round your answer to two decimal places if necessary.

The measure of segment AD in the similar triangle is 45.07 mm
Two triangles are said to be similar if they have the same shape and the ratio of their corresponding sides are in the same proportion. Also, their corresponding angles are congruent.
Triangle FEA and triangle ABC are similar triangles by the angle angle similarity postulate, therefore:
13/AD = 15 / (15 + 37)
AD = 45.07 mm
The measure of segment AD in the similar triangle is 45.07 mm
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