The correct option is c. 7
The summation of the expression [tex]\sum_{i=1}^{3}\left(4\left(\frac{1}{2}\right)^{i-1}\right)[/tex] is 7.
The sum of terms that follow a pattern is denoted by the symbol '∑' "summation," which also serves as a shorthand notation.
A sum of several terms is typically represented by the symbol "∑" This symbol is typically accompanied with a variable index that includes all terms that must be taken into account when calculating the total.
The given expression is;
[tex]\sum_{i=1}^{3}\left(4\left(\frac{1}{2}\right)^{i-1}\right)[/tex]
The the property of summation, expand the values.
[tex]\sum_{i=1}^{3}\left(4\left(\frac{1}{2}\right)^{i-1}\right)=4\left(\frac{1}{2}\right)^{1-1}+4\left(\frac{1}{2}\right)^{2-1}+4\left(\frac{1}{2}\right)^{3-1}[/tex]
[tex]\sum_{i=1}^{3}\left(4\left(\frac{1}{2}\right)^{i-1}\right)=4\left(\frac{1}{2}\right)^{0}+4\left(\frac{1}{2}\right)^{1}+4\left(\frac{1}{2}\right)^{2}[/tex]
[tex]\sum_{i=1}^{3}\left(4\left(\frac{1}{2}\right)^{i-1}\right)=4\left(\frac{1}{1}\right)+4\left(\frac{1}{2}\right)+4\left(\frac{1}{4}\right)[/tex]
[tex]\sum_{i=1}^{3}\left(4\left(\frac{1}{2}\right)^{i-1}\right)=4+2+1\\[/tex]
[tex]\sum_{i=1}^{3}\left(4\left(\frac{1}{2}\right)^{i-1}\right)=7\\[/tex]
Therefore the solution of the given equation is 7.
To know more about the summation notation, here
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The correct question is;
What is the value of [tex]\sum_{i=1}^{3}\left(4\left(\frac{1}{2}\right)^{i-1}\right)[/tex] ?
a.7/8
b.8
c.7/2
d.7