Determine if
16
x
2

25
y
2
=
1
16
x
2
-
25
y
2
=
1
is a hyperbola and if it is, which type it is. The transverse axis is
what is A and B

Determine if 16 x 2 25 y 2 1 16 x 2 25 y 2 1 is a hyperbola and if it is which type it is The transverse axis is what is A and B class=

Respuesta :

The values of a and b are 1/4 and 1/5 respectively

How to determine the true statement?

The function is given as:

16x^2 - 25y^2 = 1

The above function is a horizontal hyperbola.

A horizontal hyperbola that passes through the origin is represented as:

[tex]\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1[/tex]

Rewrite 16x^2 - 25y^2 = 1 as

[tex]\frac{x^2}{1/16} - \frac{y^2}{1/25} = 1[/tex]

By comparison, we have:

[tex]a^2 = \frac{1}{16}[/tex]

[tex]b^2 = \frac{1}{25}[/tex]

Solve for  a and b

[tex]a = \frac{1}{4}[/tex]

[tex]b = \frac{1}{5}[/tex]

Hence, the values of a and b are 1/4 and 1/5 respectively

Read more about hyperbola at:

https://brainly.com/question/27799190

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