Physics shows that when an object is thrown upward with an initial velocity of v then its approximate height v_o is given by this quadratic function.
s = − 4.9t^2 + v_ot + h

A ball is thrown upward from the top of a building 15 meters high, at a velocity of 2.8m/sec. Answer the following questions. Be sure to show and explain all work.

a) Find the maximum height and the time in which it was attained (round to 3 decimal places)
b) When does it reach the ground? (round to 3 decimal places)
c) Sketch a graph to illustrate your answers.

Physics shows that when an object is thrown upward with an initial velocity of v then its approximate height vo is given by this quadratic function s 49t2 vot h class=

Respuesta :

The maximum height of the object is 15.4 m and occurs at 0.295 sec. The object touches ground at 2.06 seconds

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

A ball is thrown upward from the top of a building 15 meters high, at a velocity of 2.8m/sec. Hence:

s = -4.9t² + 2.8t + 15

The maximum height is at s'(t) = 0, hence:

-9.8t + 2.8 = 0

t = 0.295 s

s = -4.9(0.295)² + 2.8(0.295) + 15 = 15.4 m

The object reaches ground when s = 0, hence:

0 = -4.9t² + 2.8t + 15

t = 2.06 seconds

The maximum height of the object is 15.4 m and occurs at 0.295 sec. The object touches ground at 2.06 seconds

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