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A gaseous compound containing hydrogen and carbon is decomposed and found to contain 90.00% carbon and 10.00% hydrogen by mass. The mass of 371 mL of the gas, measured at 415 mm Hg and 41°C, is found to be 0.315 g. What is the molecular formula of the compound?

Respuesta :

The molecular formula of the compound is C₃H₄.

What is the molecular formula of the compound?

The molecular formula of the compound is determined from the molecular mass of the compound.

The molecular mass of the compound is derived using the general gas equation as follows:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂/P₂T₁

Volume at STP, V₂ = (415 * 371 * 298(760 * 314)

V₂ = 192.26 mL = 0.192 L

Molar mass of gas = 22.4/0.192 * 0.315 = 36.75 g

Molecular formula is then determined from the mole ratio of the elements;

Carbon = 0.9 * 36.75/12 = 3

Hydrogen = 0.1 * 40/1 = 4

Thus, the molecular formula of the compound is C₃H₄.

In conclusion, the molecular formula of the gas is derived from the molecular mass.

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