0.592 grams of O₂ gas are needed.
What is Ideal Gas ?
An ideal gas is a gas that obeys gas laws at all temperature and pressure conditions. It have velocity and mass but do not have volume. Ideal gas is also called perfect gas.
Ideal gas law equation is expressed as:
PV = nRT
where,
P = Pressure
V = Volume (in Liters)
n = Number of moles of gas
R = Ideal gas constant
T = Temperature
Here,
P = 0.505 atm
V = 869 ml = 0.869 L
R = 0.0821 L atm/K mol [Ideal gas constant]
T = 287 K
Now put the values in above equation
PV = nRT
0.505 atm × 0.869 L = n × 0.0821 L atm/K mol × 287 K
0.438 atm L = n × 23.56 L atm / mol
[tex]n = \frac{0.438\ \text{atm L}}{23.56\ \text{L atm / mol}}[/tex]
n = 0.0185 mol
Now,
Mass of oxygen = Number of moles × Molar Mass
= 0.0185 mol × 32 g/mol
= 0.592 gram
Thus from the above conclusion we can say that 0.592 grams of O₂ gas are needed.
Learn more about the Ideal Gas here: https://brainly.com/question/20348074
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