What are the solutions of this quadratic equation?
x^2 = 16x - 65

substitute the values of a and b to complete the solutions.
x = a + bi
x = a - bi

answers:
x = 8 + i
x = 8 - i

i hope this helps.

Respuesta :

The solutions for the given quadratic equation are:

[tex]x = 8 \pm i[/tex]

How to find the solutions of the quadratic equation?

Here we have the quadratic equation:

[tex]x^2 = 16x - 65[/tex]

We can rewrite it as:

[tex]x^2 - 16x + 65 = 0[/tex]

Using Bhaskara's formulas, we get:

[tex]x = \frac{-(-16) \pm \sqrt{(-16)^2 - 4*65} }{2} \\\\x = \frac{16 \pm \sqrt{(-4)} }{2}[/tex]

Now, remember that:

[tex]\sqrt{-1} = i[/tex]

Then we can rewrite:

[tex]x = \frac{16 \pm \sqrt{-1} *\sqrt{4} }{2}\\\\x = 8 \pm i[/tex]

If you want to learn more about quadratic equations:

https://brainly.com/question/1214333

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