The parents could have 3 boys and 3 girls in 400 ways
The given parameters are
Children, n = 6
Boys, r = 3
Girls, r =3
The number of combination is:
[tex]Ways = ^nC_{r1} *^nC_{r2}[/tex]
So, we have:
[tex]Ways = ^6C_3 *^6C_3[/tex]
Apply the combination formula
[tex]Ways = \frac{6!}{3!3!} *\frac{6!}{3!3!}[/tex]
This gives
Ways = 400
Hence, the parents could have 3 boys and 3 girls in 400 ways
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