The ordered pairs which is the solution of the system of Inequalities is;
x > 0 and y < 2
How to find the ordered pair of inequalities?
We are given the inequalities;
x + 2y > 4 ----(1)
3x - y < 2 -----(2)
Subtract 2y from both sides in eq 1 to get;
x > 4 - 2y ----(3)
Put 4 - 2y for x in eq 2 to get;
3(4 - 2y) - y < 2
12 - 4y - y < 2
12 - 5y < 2
Subtract 12 from both sides to get;
-5y < -10
Divide both sides by -5 to get;
y < 2
Put 2 for y in eq 3 to get;
x > 4 - 2(2)
x > 0
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