Yes, (3, -2) is a solution for the linear system y = 2x - 8 and 2x + 4y = -2
In mathematics, the theory of linear systems is the foundation and core part of linear algebra, a subject that is used in most parts of modern mathematics. When the number of equations is the same as the number of variables, there is likely to be a solution. Not guaranteed, but likely.
If there is no solution, the equations are called "inconsistent".
One or infinitely many solutions are called "consistent"
In mathematics, a system of linear equations is a set of one or more linear equations involving the same variables
We need to find whether (3, -2) is a solution for the linear system y = 2x - 8 and 2x + 4y = -2 or not
Let y = 2x - 8.......(1)
From equation (1) we get, y - 2x = -8.....(2)
2x + 4y = -2.........(3)
Put (3,-2) in equation (2) , we get
-2 - 2(3) = -2 -6 = -8
LHS = RHS
Put (3,-2) in equation (3) , we get
2(3) + 4(-2) = 6 - 8 = -2
LHS = RHS
Hence,(3, -2) is a solution for the linear system y = 2x - 8 and 2x + 4y = -2
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