Suppose 60% of the freshmen at msu take a course in outdoor survival skills. the probability that a freshman selected at random who did not get lost during a hike is 90%. the probability that a freshman selected at random who took the course and did not get lost is 50%.

Respuesta :

Probability that a freshman selected at random who took the course and did not get lost and Probability of freshmen who took course at MSU in outdoor survival skills is 0.8333

According to the question,

Probability of freshmen who took course at MSU in outdoor survival skills is 0.6.

Probability that a freshmen selected at random who did not get lost during a hike is 0.9.

Probability that a freshman selected at random who took the course and did not get lost is 0.50

Conditional probability = P(A and B)/ P(A)

P(did not get lost/took the course) = P( freshmen did not get lost who took the course and freshmen took the course)/P(freshmen did not get lost)

= 0.5/0.6

= 0.8333

Hence, Probability that a freshman selected at random who took the course and did not get lost and Probability of freshmen who took course at MSU in outdoor survival skills is 0.8333

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