Using Algebraic equation, Kathy worked 22 hours at job A and 12 hours at job B, the week she made US $ 140.60.
Let's review all the information given for solving this question:
Rate per hour of Job A = US$ 6.20
Rate per hour of Job B = US$ 6.50
Earnings received by Kathy during the week = US$ 140.60
Total time worked by Kathy during the week = 22hours
Hours at job A = x
Hours at job B = 22 -x
In order to find how many hours Katy worked at each job: This is the Algebraic equation that we'll use:
6.20x + 6.50 (22 - x) = 140.60
6.20x + 143- 6.50x = 140.60
-0.3x = 140.60 - 143
-0.3x = - 2.4
x = -(2.4)/-(0.3)
x = 14.3/0.3 = 8 (Dividing by 0.3 at both sides)
Kathy worked 8 hours at job A.
Hours at job B = 22 - x. Put x = 11 we get
Hours at job B = 22 -11
= 11
Hence, using Algebraic equation Kathy worked 22 hours at job A and 12 hours at job B, the week she made US $ 140.60.
Learn more about Algebraic equation here
https://brainly.com/question/14781054
#SPJ4