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y = -3/4x + 14 is the answer.
y = 4/3x+ 7...slope here is 4/3. A perpendicular will have a negative reciprocal slope. All that means is to flip the slope and change the sign.
4/3....flip it....3/4....change the sign....-3/4. So our perpendicular equation has to have a slope of -3/4
y = mx + b
slope(m) = -3/4
(4,11)...x = 4 and y = 11
now we sub and find b, the y int
11 = -3/4(4) + b
11 = - 3 + b
11 + 3 = b
14 = b
so ur line is : y = -3/4x + 14
The perpendicular line has the opposite slope of the reciprocal, so the slope of the line you want to find is 1/2. Inserting the given points into the equation y = 1 / 2x + b and solving b yields b = 6. Therefore, the linear equation is y = ½x + 6. When relocated, it becomes –x / 2+. y = 6.
Q) What is the equation of the line that passes through the point (4,11) and is perpendicular to the line with the following equation y = 4/3x + 7
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