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Three times got the prize money worth $126,000. the first friend would get three times the amount of the third friend's portion. the third friend would get twice the amount of the second friend's portion. determine the amount that each friend would receive.

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sakshigupta4990

128000.

Let the three frithe ends x, y, z x is the first friend y is secmy ond friend

z is third friend

X+y+z=128000  

x=4z    

z=3y    

x=4(3y)=12y   put values of x and z in the first equation we got

12y+y+3y=128000

16y=128000

= 128000 - = 8000 16

Put the y value in equation 3 wee got

z=3*8000=24000

Put the z value in equation 2 we got

x=4*24000=96000

8000+24000+96000=128000.

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https://brainly.com/question/2972832

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