aiueo8637 aiueo8637

19-07-2022
Chemistry

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The procedure calls for 2.0 ml of concentrated nitric acid. how many moles is this?

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raymundocelis19 raymundocelis19

19-07-2022

Answer:

ρHNO₃= 1.51 g/cm3

ρ = m/V

m = ρ x V

m = (1.51 g/cm3)(2 cm3)= 3.02 g de HNO₃

n = m/PM = 3.02 g/63.01 g/mol = 0.0479 mol de HNO₃

Explanation:

2 mL of concentrated nitric acid equals 0.0479 mol

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