Respuesta :
The derivatives of y=[tex]2x^{3}+5x^{2} +4x-9[/tex] is [tex]6x^{2} +10x+4[/tex], derivative of y=[tex]2x^{2} +3x+5[/tex] is 4x+3, derivative of [tex](5x^{2} -9)6[/tex] is 60x.
Given three functions y= [tex]2x^{3}+5x^{2} +4x-9[/tex], y=[tex]2x^{2} +3x+5[/tex], y=[tex](5x^{2} -9)6[/tex].
We have to find the derivative of functions.
Derivative of a function of a real variablemearsures the sensitivity to change of the function value with respect to a chaneg in its argument. Derivatives are a fundamental tool of calculas.
First function: y=[tex]2x^{3}+5x^{2} +4x-9[/tex], derivative can be as under:
dy/dx=2*3[tex]x^{2}[/tex]+2*5x+4 (derivative of x is 1)
(d[tex]x^{n}[/tex]/dx=n[tex]x^{n-1}[/tex])
dy/dx=6[tex]x^{2}[/tex]+10x+4
Second function: y=[tex]2x^{2} +3x+5[/tex], derivative can be as under:
dy/dx=2*2x+3
=4x+3
Third function:y=[tex](5x^{2} -9)6[/tex]
dy/dx=5*2x*6
=10x*6
=60x
Hence the derivative of first function is [tex]6x^{2} +10x+4[/tex], second function is 4x+3, third function is 60x.
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