The rational numbers are -5/250, [tex]\sqrt{400}[/tex] ,and irrational numbers are 5.012121212......., [tex]\sqrt[3]{30}[/tex] , 0.01562138411........,[tex]\sqrt{1000}[/tex]
Given six numbers:5.012121212..,[tex]\sqrt{1000}[/tex],[tex]\sqrt[3]{30}[/tex], -5/250, 0.01562138411.....,[tex]\sqrt{400}[/tex].
We have to identify which numbers are rational and which are irrational numbers.
Rational numbers are those numbers which can be written in p/q form where q cannot be equal to zero because if q is zeo then the value of p/q will be infinity.
Irrational numbers are those numbers which cannot be written in p/q form.
First number :5.0121212121....
In the above numbers 12 is repeating next to the decimals. So it is a irrational numbers.
Second number:[tex]\sqrt{1000}[/tex]
If we solve the above number we will find it 31.6227766017 . It is cannot be expressed in p/q form, so it is irrational number.
Third number:[tex]\sqrt[3]{30}[/tex]
The abov number is irrational number as we cannot express it in p/q form.
Fourth number:-5/250
The value of above number is -0.02.It can be in the form of -2/100. so it is rational number.
Fifth number:0.01562138411........
Because the digits are repeating after decimals so it is irrational number.
Sixth number:[tex]\sqrt{400}[/tex]
The value of above number is 20, so it is rational number.
Learn more about rational numbers at https://brainly.com/question/12088221
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Question is incomplete as it should include figure.
