Answer:
a) x = 1, x = -7
b) (-3, -48)
c) x = -3
d) upwards
Step-by-step explanation:
Given quadratic equation:
[tex]y=3(x-1)(x+7)[/tex]
Part (a)
Intercept form of a quadratic equation:
[tex]y=a(x-p)(x-q)[/tex]
where:
- p and q are the x-intercepts
- a is some constant
Comparing the formula with the given equation:
⇒ p = 1
⇒ q = -7
Therefore, the x-intercepts of the given equation are x = 1 and x = -7.
Part (b)
The midpoint between the two x-intercepts is the x-coordinate of the vertex.
[tex]\implies \textsf{Midpoint}=\dfrac{x_2+x_1}{2}=\dfrac{1+(-7)}{2}=-3[/tex]
Therefore, the x coordinate of the vertex is -3.
To find the y-coordinate of the vertex, substitute this into the given equation:
[tex]\implies y=3(-3-1)(-3+7)=-48[/tex]
Therefore, the coordinates of the vertex are (-3, -48).
Part (c)
The x-coordinate of the vertex is the axis of symmetry.
Therefore, the axis of symmetry is x = -3.
Part (d)
If the leading coefficient of a quadratic equation is positive, the parabola opens upwards.
If the leading coefficient of a quadratic equation is negative, the parabola opens downwards.
From inspection of the given equation, the leading coefficient is 3.
Therefore, the parabola opens upwards.
Learn more about quadratic equations here:
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