Point [tex](1,5)[/tex] is a solution of the equation [tex]g(x)=3x+2[/tex] and point [tex](1,5)[/tex] is not a solution of equation [tex]f(x)=|x-1|+1[/tex]
Why point [tex](1,5)[/tex] is solution of the equation [tex]g(x)=3x+2[/tex] ?
If point [tex](1,5)[/tex] is solution of the equation then they must satisfy the equation.
So we need to check one by one
[tex](x,y)=(1,5)[/tex]
equation [tex]g(x)=3x+2[/tex]
We can write as
[tex]y=3x+2\\5=3*1+2\\5=5[/tex]
So point [tex](1,5)[/tex] is solution of this equation.
Equation [tex]f(x)=|x-1|+1[/tex]
We can write as
[tex]y=|x-1|+1\\5=|1-1|+1\\5=0+1\\5\neq 1[/tex]
So point [tex](1,5)[/tex] is not solution of equation [tex]f(x)=|x-1|+1[/tex]
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