The velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.
The velocity of the boy when he hits the water at the bottom of the slide is calculated from the principle of conservation of energy.
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
v = √(2 x 9.8 x 10)
v = 14 m/s.
Thus, the velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.
Learn more about velocity here: https://brainly.com/question/6504879
#SPJ1