A welding torch requires 4122.8l of ethylene gas at 0.64 atm what will be the pressure of the gas if ethylene is supplied by a 51.6 l tank

Respuesta :

The pressure of the gas if ethylene is supplied by a 51.6 l tank is 51.1355atm

The final pressure of the gas can be calculated by using the formula given by Boyle's law,

      P1V1 = P2V2

What is Boyle's law?

    Boyle's law relates the compression and expansion of gas at a constant temperature. It states that, At constant temperature the pressure exerted by a gas is inversely proportional to the volume of the given mass of gas.

      P1V1 = P2V2

where,

P1 is the initial pressure

V1 is the initial volume

P2 is the final pressure and

V2 is the final volume.

Given data:

Initial volume V1= 4122.8L

Initial pressure P1= 0.64atm

Final volume V2= 51.6L

Final pressure P2= ?

   0.64*4122.8= P2*51.6

   P2= 2638.592/51.6

   P2= 51.1355atm

Hence the final pressure of the gas is 51.1355atm

Learn more about Boyle's law on

https://brainly.com/question/1696010

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