1 point
Calculate the rate of change for each function over the interval [0, 3], then tell which function is
growing faster.
f(x) = 2x + 3
g(x) = 2² +3
Of(x) has a rate of change of 2
g(x) has a rate of change of 2.33
So g(x) is growing faster
f(x) has a rate of change of 6
g(x) has a rate of change of 7
So g(x) is growing faster
f(x) has a rate of change of 6
g(x) has a rate of change of 7
So f(x) is growing faster
f(x) has a rate of change of 2
g(x) has a rate of change of 2.33
So f(x) is growing faster

Respuesta :

If f(x) = 2x + 3 then Δy/Δx = 2 and g(x) = 2² +3 then Δy/Δx = 2.33.

The correct answer is option A.

f(x) has a rate of change of 2

g(x) has a rate of change of 2.33

So g(x) is growing faster

How to estimate the rate of change of a function over the interval  [0, 3]?

Let f(x) = 2x + 3 and g(x) = 2² +3

Let, ∆y /∆x denotes the ratio of y change and x change when x change exists relatively large.

If f(x) = 2x + 3

Δy/Δx = [f(3) - f(0)]/3 - 0

f(3) [tex]= 2*3+3 = 9[/tex]

f(0) [tex]= 2*0+3 = 3[/tex]

[f(3) - f(0)]/3 - 0 = (9 - 3)/3

= 6/3 = 2

g(x) = 2² +3

Δy/Δx = [g(3) - g(0)]/3 - 0

[tex]$= (2^3 +3)-(2^0 +3)/3[/tex]

[tex](2^3 +3)-(2^0 +3) = 7[/tex]

[tex](2^3 +3)-(2^0 +3)/3[/tex] = 7/3 = 2.33

Therefore, the correct answer is option A.

f(x) has a rate of change of 2

g(x) has a rate of change of 2.33

So g(x) is growing faster

To learn more about functions refer to:

https://brainly.com/question/11388036

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