find the area of the following

Answer:
24000 ft²
Step-by-step explanation:
b = base = PR = 240 ft
2AS = 240 ft
[tex]\sf AS = \dfrac{240}{2}\\\\ AS = 120 \ ft[/tex]
h = height = AS = 120 ft
[tex]\sf \boxed{\bf \ Area \ of \ triangle = \dfrac{1}{2}b*h}[/tex]
[tex]\sf =\dfrac{1}{2}*240*120\\\\ = 120 * 120\\\\ = 14400 \ ft^2[/tex]
b = PR = 240 ft
3BQ = 240 ft
[tex]\sf BQ = \dfrac{240}{3}\\\\ BQ = 80 \ ft[/tex]
[tex]\sf Area \ of \ triangle \ PRQ = \dfrac{1}{2}*240*80[/tex]
= 120 * 80
= 9600 ft²
Area of the quadrilateral PQRS = area of ΔPRS + area of ΔPRQ
= 14400 + 9600
= 24000 ft²