Adewale09
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A proton moving along the positive x-axis enters a uniform magnetic field which is directed along the
positive y-axis. If the magnitude of the field is 0.7 T, and the charge and speed of the proton are 1.5 x10-19 C
and 3.0 x 106 m/s respectively. Calculate the force acting on the proton​

Respuesta :

Nandhitha1098

Answer: The force acting on the proton of charge ​1.5 x10-19 C moving with velocity 1.5 x10-19 C under the influence of a magnetic field of 0.7 T will be 3.15×10^-13 N.

Explanation: To find the answer we need to know more about the Lorentz magnetic force.

What is the Lorentz magnetic force acting on the proton?

  • Consider a proton of charge q moving with a velocity v in a magnetic field, then the Lorentz magnetic force exerted on the proton can be expressed as,

                                  F= q (v× B)

                               [tex]F= qvBsin\alpha[/tex]  where, [tex]\alpha[/tex] is the angle between v and B.

  • In the question, it is given that,

                                [tex]B=0.7 T\\q=1.5*10^{-19}C\\v= 3*10^{6}m/s.\\\alpha =90 degree.\\[/tex] because, from the question it is clear that the proton is moving along x axis and the magnetic field is along the y axis.

  • Thus, we can find the force acting on the proton as,

                      [tex]F=qvBsin\alpha =1.5*10^{-19}C*3*10^6 m/s*0.7T*sin (90)\\F=3.15*10^{-13}N[/tex]

Thus, we can conclude that the Lorentz force acting on the proton will be 3.15×10^-13 N.

Learn more about the Lorentz magnetic force here:

https://brainly.com/question/28047923

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In response to a magnetic field of 0.7 T, a proton with a charge of 1.5 x 10-19 C travelling at a speed of 1.5 x 10-19 C will experience a force of 3.15 x 10^-13 N.

We need to learn more about the Lorentz magnetic force in order to locate the solution.

What does the proton experience as the Lorentz magnetic force?

  • If you imagine a proton with charge q travelling at speed v in a magnetic field, you can write down the Lorentz magnetic force acting on the proton as,

                                      F= Q (v× B)

                                   [tex]F=QvBsin\alpha[/tex]

[tex]\alpha[/tex] the angle between v and B is, where.

  • It is stated in the query that, the magnetic field is along the y axis and the proton is travelling along the x axis. Thus, the angle will be 90 degrees.
  • As a result, we can identify the proton's driving force as,

                           [tex]F=3.15*10^{-13}N[/tex]

Thus, we can infer that the proton will be subject to a 3.15 10^-13 N Lorentz force.

Learn more about the electromagnetic force here:

https://brainly.com/question/11961868

#SPJ1

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