A pea plant purebred to produce round yellow peas is crossed with a plant purebred to produce wrinkled green peas. Round pea shape is dominant to wrinkled, and yellow pea color is dominant to green. Members of the resulting F1 generation are then crossed to produce an F2 generation, as shown in the figure. On average, what fraction of the F2 generation will display both dominant traits?

(ANSWER ONLY IF YOU ARE SURE PLEASE NO GUESSING THANK YOU)
A)


4 out of 16 plants will display both dominant traits.


B)


9 out of 16 plants will display both dominant traits.


C)


16 out of 16 plants will display both dominant traits.


D)


12 out of 16 plants will display both dominant traits.

A pea plant purebred to produce round yellow peas is crossed with a plant purebred to produce wrinkled green peas Round pea shape is dominant to wrinkled and ye class=

Respuesta :

Oseni

The fraction of the F2 generation that will display dominant traits will be 9/16. The correct option is B.

Dihybrid cross

Let us assume that pea shape is represented by A (a) while color is represented by B(b).

Purebred round yellow peas = AABB

Purebred wrinkled green peas = aabb

            F1:     AABB  x  aabb

                         all AaBb

            F2:      AaBb   x   AaBb

A_B_ = 9/16

A_bb = 3/16

aaB_ = 3/16

aabb = 1/16

Thus, the fraction of the F2 offspring with both dominant traits. A_B_, is 9/16.

More on dihybrid crosses can be found here: https://brainly.com/question/1185199

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