The correct option regarding whether the equation x² = y² is a function is:
No, since if you solve the equation for x, then [tex]x = \pm y[/tex]
What is needed for a relation to represent a function?
In a function, each value of x can be associated with only one value of y.
In this problem, the equation is:
[tex]x^2 = y^2[/tex]
Then:
[tex]x = \pm \sqrt{y^2}[/tex]
[tex]x = \pm \sqrt{y}[/tex]
x is associated with two values, [tex]-\sqrt{y}[/tex] and [tex]\sqrt{y}[/tex], hence it is not a function.
A similar problem, in which we verify if a relation is a function, is at https://brainly.com/question/12463448
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