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NEED HELP asap pls
How much thermal energy must be removed from 3.75 kg of
water to freeze it at its melting point? Use Q = mass x latent
heat of fusion.
Melting point
Boiling point
OA. 15.8 kJ
B. 1250 kJ
Cliquid
Latent heat of fusion.
Latent heat of vaporization
C. 3.75 kJ
Properties of water
Property
D. 8480 kJ
0°C
Value
100°C
4.18 kJ/(kg x °C)
333 kJ/kg
2260 kJ/kg

NEED HELP asap pls How much thermal energy must be removed from 375 kg of water to freeze it at its melting point Use Q mass x latent heat of fusion Melting poi class=

Respuesta :

pstnonsonjoku

The heat that is required to freeze the water is 1250 kJ. Option B

What is the freezing point?

The freezing point of water is the temperature at which liquid water turns to solid. We know that heat is withdrawn from water when it is frozen. This heat is added when the water melts.

The latent heat of fusion = mL

m =  3.75 kg

L = 333kJ/Kg

Hence;

H =  3.75 kg * 333kJ/Kg

H = 1250 kJ

Learn more about heat of fusion:https://brainly.com/question/14053504

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