The triangle is an isosceles triangle and the four triangles are similar
The coordinates are given as:
A (0, 0), B (5, 0), and C (2, 4).
Calculate the distance between the coordinates using:
[tex]d = \sqrt{(x_2 -x_1)^2 +(y_2 -y_1)^2[/tex]
So, we have:
[tex]AB = \sqrt{(0 -5)^2 +(0-0)^2} =5[/tex]
[tex]AC = \sqrt{(0 -2)^2 +(0-4)^2} =4.5[/tex]
[tex]BC = \sqrt{(5 -2)^2 +(0-4)^2} =5[/tex]
The above shows that two sides are congruent.
Hence, the triangle is an isosceles triangle
This is calculated using:
(x, y) = 0.5 * (x1 + x2, y1 + y2)
So, we have:
AB = 0.5 * (0 + 5, 0 + 0) = (2.5, 0)
AC = 0.5 * (0 + 2, 0 + 4) = (1, 2)
BC = 0.5 * (5 + 2, 0 + 4) = (3.5, 2)
From the attached graph, we can see that the triangles are similar
Read more about similar triangles at:
https://brainly.com/question/14285697
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