The expression of the given logarithmic function 2log(2/√5) is; D: -0.097
How to solve Logarithmic Functions?
From logarithmic Identities, we know that;
log (x/y) = log x - log y
log (x * y) = log x + log y
Thus;
2log(2/√5) = 2[log 2 - log √5)
Now, log √5 can also be expressed as;
log √5 = ¹/₂log 5
Thus;
2log(2/√5) = 2[log 2 - ¹/₂log 5]
⇒ 2 log 2 - log 5
We are given the values;
log2≈0.301, log3≈0.447, log4≈0.602, log5≈0.699
Thus;
2log(2/√5) = 2 log 2 - log 5 = 2(0.301) - 0.699
⇒ -0.097
Read more about Logarithmic Function Identities at; https://brainly.com/question/10208274
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