Iodine-131 has a half-life of 8 days. If you start with a sample of 150 grams, how much of the original isotope will remain after 30 days?

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pstnonsonjoku pstnonsonjoku · Answer 1 · 2022-07-19T16:33:42+02:00

The amount of the original isotope that remains after 30 days is 11.14.

The half life of a radioactive nuclide has to do with the time that it takes for only half of the original number of nuclides to remain.

Now;

No = 150 grams

N = ?

t1/2 = 8 days

t = 30 days

Then;

N/No = (1/2)^t/t1/2

N/150 = (1/2)^30/8

N/150 = (1/2)^3.75

N = (1/2)^3.75 * 150

N = 11.14

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mickymike92 mickymike92 · Answer 2 · 2022-07-19T16:33:55+02:00

Given the half-life, the amount remaining is 11.14 g

The half-life of idine-131 is 8 days.

Using the half-life formula:

Nt = No * (0.5)^(t/t1/2)

Amount remaining = 150 * (05)^(30/8)

Amount remaining = 11.14 g

In conclusion, the amount remaining is determined from the half-life of the substance.

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