The probability that he gets fewer than 3 of them correct is : 0.80
The problem is a Binomial problem
n = 8
P(correct ) = 1/5
P( 0<= x <=2 ) = binomcdf ( 8, 1/5, 2)
= ⁸C₂(1/5)² (4/5)⁶ + ⁸C₁(1/5)(4/5)⁷ + ⁸C₀(4/5)⁸
= 0.7969 ≈ 0.80
Hence we can conclude that The probability that he gets fewer than 3 of them correct is : 0.80
Learn more about binomial probability : https://brainly.com/question/9325204
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