Since the value of f(5) is zero, hence x – 5 a factor of the function f(x) = x^3 – 5x^2 + 7x – 35,
Remainder theorem
In order to determine whether x – 5 a factor of the function f(x) = x^3 – 5x^2 + 7x – 35, we will show that f(5) = 0
Substitute x = 5 into the function to have;
f(5) = 5^3 – 5(5)^2 + 7(5) – 35
f(5) = 125 - 125 + 35 - 35
f(5) = 0
Since the value of f(5) is zero, hence x – 5 a factor of the function f(x) = x^3 – 5x^2 + 7x – 35,
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