The values of x that will give the quadratic equation no real number solutions are -5 and 9
What are real roots of a quadratic equation?
Real roots of a quadratic equation are values of x, whose numbers can be represented on a number line.
Analysis:
We have -[tex]x^{2}[/tex] +3x +c = 0
[tex]b^{2}[/tex] - 4ac is called the discriminant of a quadratic equation.
if [tex]b^{2}[/tex] - 4ac < 0, then the quadratic equation has no real root.
where a = -1, b = 3 c = c
[tex](3)^{2}[/tex] -4(-1)c < 0
9 + 4c < 0
4c < -9
c < -9/2
Which means values lower than -9/2 would give the solution no real root.
From, the options, only -5 would give no real solution, since it is lower than -9/2.
Learn more about real roots of a quadratic equation: brainly.com/question/7784687
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