There are x students in Mrs. Schwartz's third-grade class. One fewer than half the students have brown eyes. Six fewer children have blue eyes than have brown eyes. The rest of the students have green eyes. How many students have green eyes?

F. 8
E. 7
G. x/2-7
H. x - 8

Brown Eyes: 1/2x - 1
Blue Eyes: 1/2x-6

Let the students who have green eyes be y.

1/2x-1+1/2x-6= x-y (Because the RHS is the students with brown and blue eyes and hence x-y on the LHS)
x-7=x-y
-y=-7
y=7

Therefore 7 students have green eyes.
(E)

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There are x students in Mrs. Schwartz's third-grade class. One fewer than half the students have brown eyes. Six fewer children have blue eyes than have brown eyes. The rest of the students have green eyes. How many students have green eyes? F. 8 E. 7 G. x/2-7 H. x - 8

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There are x students in Mrs. Schwartz's third-grade class. One fewer than half the students have brown eyes. Six fewer children have blue eyes than have brown eyes. The rest of the students have green eyes. How many students have green eyes?

F. 8
E. 7
G. x/2-7
H. x - 8