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Two 5000-kg passenger cars roll without friction (one at 1 m/s, the other at 2 m/s) toward one another on a level track. They collide, couple, and roll away together with a combined momentum of

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onyebuchinnaji

The combined momentum of the passengers is 5000 kgm/s.

Combined momentum of the passenger

The combined momentum of the passengers is calculated as follows;

P = mv1 + mv2

where;

  • m is mass of the passengers
  • v1 is velocity of the first passenger
  • v2 is velocity of the second passenger

P = m(v1 + v2)

P = 5000(-1 + 2)

P = 5000 kgm/s

Thus, the combined momentum of the passengers is 5000 kgm/s.

Learn more about momentum here: https://brainly.com/question/7538238

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