The concentration of the acetic acid before titration is 0.128M
For weak acid and strong base titration-
Moles of acetic acid = moles of NaOH
Given concentration of NaOH = 0.1067M
Volume of NaOH = 30.07ml = 0.03007L
Using the formula, Concentration = Moles/Volume
Moles of NaOH = concentration X volume = 0.1067 X 0.03007 = 0.0032
Therefore, moles of acetic acid = 0.0032mole
Using the formula, Concentration = Moles/Volume
Concentration of acetic acid = 0.0032/0.025 = 0.128M
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